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− | Incidentally, the initial hexagon you have made is another example of a |
+ | Incidentally, the initial hexagon you have made is another example of a [[Tori|torus]]. |
− | torus, see [[Wikia|Tori]]. |
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== Building Instructions == |
== Building Instructions == |
Revision as of 06:23, 30 August 2008
Diamond lattice | |
' | |
Type | Polyhedron |
Rods | (12+12)N × |
Spheres | 6 N × |
Author | --Leo Dorst 9:10, 30 August 2008 (UTC)L.Dorst |
The diamond lattice gets its strength from the intricate interconnectedness of its basic carbon atoms.
This model shows how each (yellow) carbon atom is connected (in red) to 4 other atoms, in a manner that makes it a part of 12 hexagons, in 4 planes.
Building Instructions
Even though in an infinite lattive there are as many rods in the atoms as there are in the connections, a finite lattice stops at the atoms. Therefore use your most numerous color for those atoms.
- First make the atoms as octahedra. Each octahedron will get connections in tetrahedral directions to 4 other atoms.
- Start making a simple hexagon out of 6 atoms, connecting the atoms in pairs. You will find that they are alternatingly in 2 planes, the hexagon is a bit 'wavy'.
- Now from this hexagon expand in the other directions, constructing more of them, and the lattice will take shape by itself.
- Stop when you run our of rods.
Incidentally, the initial hexagon you have made is another example of a torus.