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This support structure is amazingly close. It consists of five intersecting tetrahedra, connected to the spheres in the rhombic triacontahedron with valency 3. The size of the edges of the tetrahedra is 3 rods.

## Building Instructions

1. Build the lower halve of the rhombic triacontahedron.
2. Start putting support rods in (3 connected rods).
• Basically it suffices to connect one side to a sphere of valency 3, and see to which sphere of valency 3 the other side leads you.
• Also keep a look out for the five intersecting tetrahedra that develop.
3. Complete the upper halve of the rhombic triacontahedron.
4. Put in the remaining support rods.

## Calculations

This model is indeed a very near miss.

The support struts may be seen as "step three diagonals" of the dodecahedron formed by the points of the intersecting tetrahedra.

This strut is itself the diagonal of a square whose sides are formed by the inscribed pentagram on the dodecahedral faces, which have length the golden ratio, phi (=1.618approx) [this is a "root-two-phi bar" see ???]

So, the support strut is sqrt(2) times phi times the length of the dodecahedral edge.

The dodecahedral edge is the short diagonal of the golden rhombus of the rhombic triacontahedron: this length is 4/sqrt(10+2*sqrt(5)) (1.051 approx).

It's the same as the inverse of the circumradius of the icosahedron, see Mathworld

Multiplying all these together gives us the geometric ratio between the rhombic triacontahedron edge length and the support strut.

• Geometric ratio = 2.406
• Actual geometric distance = 93.45mm
• Length of strut = 3 bars + 0.61mm

We know that once the error gets down to around half a millimetre, the structure can usually absorb it.

A very small smile is permitted.

## Related Links

Voted: --Karl Horton 09:10, 9 August 2007 (UTC)

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