Karl Horton (talk | contribs) m |
Karl Horton (talk | contribs) m |
||
Line 12: | Line 12: | ||
{{clr}} |
{{clr}} |
||
== Calculations == |
== Calculations == |
||
− | let alpha = arcsin(1/sqrt(3)) = 35.264 degrees, be the semi |
+ | let alpha = arcsin(1/sqrt(3)) = 35.264 degrees, be the semi-apex angle of an equilateral square-based prism. |
+ | |||
+ | (A mnemonic for this is that the inclination of a face is 54.7 degrees, which is the complement, and is half the well-known "bond angle of methane" at 109 degrees 28 minutes, which I've always remembered for some reason). |
||
Then each segment of the curve moves through 2*alpha - 60 degrees = 10.528 degrees |
Then each segment of the curve moves through 2*alpha - 60 degrees = 10.528 degrees |
Revision as of 20:24, 3 June 2007
Definition
[[{{{PageTitle}}}|Suspended Circle ]] | |
Type | Abstract |
Panels | 44 × |
Rods | 353 × |
Spheres | 131 × |
Author | Jeffkoslo 22:05, 3 May 2007 (UTC) |
A fully suspended closed circle on two support legs. The loop is composed of 34 segments, alternating trianges with pyramids.
Building Instructions
- Create the bottom arc of 9 segments.
- Add the support legs downward from the ends of the arc.
- Continue adding segments upwards to complete the entire circle.
- Keep the two sides balanced as you are building upwards.
Calculations
let alpha = arcsin(1/sqrt(3)) = 35.264 degrees, be the semi-apex angle of an equilateral square-based prism.
(A mnemonic for this is that the inclination of a face is 54.7 degrees, which is the complement, and is half the well-known "bond angle of methane" at 109 degrees 28 minutes, which I've always remembered for some reason).
Then each segment of the curve moves through 2*alpha - 60 degrees = 10.528 degrees
So, 34 segments move trough 357 degrees, which is close enough to absorb.
Examples
Community content is available under CC-BY-SA unless otherwise noted.